(20t^2+t)^2-22(20t^2+t)+21=0

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Solution for (20t^2+t)^2-22(20t^2+t)+21=0 equation: 



(20t^2+t)^2-22(20t^2+t)+21=0

We multiply parentheses

-440t^2+(20t^2+t)^2-22t+21=0

We add all the numbers together, and all the variables

-440t^2-22t+(20t^2+t)^2+21=0

We move all terms containing t to the left, all other terms to the right

-440t^2-22t+(20t^2+t)^2=-21

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